Can u plz help me doing this question above
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hi, frns its very easy
formula to remember=sum of all the angles I'm a quadrilateral is 360degree
sum of all angles of quadrilateral is 360degree
so, 112+90+70+x=360
112+160+X=360
272+X=360
x=360-272
X=88
Now x+z=180(linear pair)
88+z=180
Z=180-88
Z=92
let the angle partner of 70 be w
then70+w=180(linear pair)
w=110
sum of all angles will be 360
so,
90+92+110+Y=360
182+110+Y=360
292+y=360
Y=360-292
Y=68
Say NO toRACISM
formula to remember=sum of all the angles I'm a quadrilateral is 360degree
sum of all angles of quadrilateral is 360degree
so, 112+90+70+x=360
112+160+X=360
272+X=360
x=360-272
X=88
Now x+z=180(linear pair)
88+z=180
Z=180-88
Z=92
let the angle partner of 70 be w
then70+w=180(linear pair)
w=110
sum of all angles will be 360
so,
90+92+110+Y=360
182+110+Y=360
292+y=360
Y=360-292
Y=68
Say NO toRACISM
puvahjames:
follow me frns
Answered by
0
y= 360-(92 + 90+ 110)= 68 degree
x=88 degree because 70 + 112 + 90 + x = 360 so x = 360- 272 = 88
z = 180-88 = 92 degree ( angles formed on a straight line ) so they are a linear pair.
x=88 degree because 70 + 112 + 90 + x = 360 so x = 360- 272 = 88
z = 180-88 = 92 degree ( angles formed on a straight line ) so they are a linear pair.
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