Can u plz help me to find areas of no.26&29
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Answer:
26)Option E
27)Option A
Step-by-step explanation:
26)Area of shaded part
=Area of rectangle-Area of triangle (unshaded part)
=length×breadth-½×base×height
=(15×22)-(½×10×15)
=(15×22)-(5×15)
=330-75
=255m²
Option E
29)Area of cube when top is opened
=5a²
=5(18)²
=5(324)
=1620m²
Option A
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