Math, asked by Deepak109473, 1 year ago

can u plz solve this......... its urgent i need it within 2 hours

Attachments:

Shriannshi: The ratio of 5th and 3rd term is 2:5?
Deepak109473: no
Deepak109473: its 2.5
Deepak109473: btw
Deepak109473: r u a girl?

Answers

Answered by Ramsor
0

Answer:

I HOPE U GET UR SOLUTION PLS GIVE ME 5 STARS

Step-by-step explanation:

let first term =a , common difference =d of an AP

third term = a3 = a+2d

5th term = a5 = a+4d

ratio = 2/5

(a+4d)/(a+2d) = 2/5

5(a+4d) = 2(a+2d)

5a+20d = 2a +4d

5a-2a = 4d -20d

3a= -16d

a= -16d/3 ---(1)

ratio of 15th term and 7th term = (a+14d)/(a+6d)

= [-16d/3 +14d]/[-16d/3 +6d] from (1)

= [-16d +42d]/ [ -16d +18d]

= 26d/2d

=13/1

=13:1

Answered by shanayamathur114
0


Step-by-step explanation:


Attachments:

shanayamathur114: sorry it
Deepak109473: for what?
Deepak109473: ur class?
shanayamathur114: Now I am in 10th
shanayamathur114: What about you???
Deepak109473: me also 10 th
Deepak109473: how is preparation for boards?
shanayamathur114: It is going on in full swing
shanayamathur114: How is your preparation for boards?
Similar questions