Question

can u plzz explain the davisson germer experiment with its complete derivation and figure required hand written answer​

Answer 1

DAVISSON AND GERMER EXPERIMENT:

Electrons from hot tungsten cathode (C) are accelerated by the potential difference V between cathode and anode (A). A narrow hole in the anode renders the e- into a fine beam of e- & allows it to strike the Ni crystal. The electrons are scattered in all directions by the atom in the crystal. The intensity of the e- beam scattered in given direction is found by the use of detector. By rotating the detector about an axis through a point O, the intensity of the scattered beam can be measured for different values of phi, the angle between incident and the scattered direction of e- beam.

Explanation:

The selective refelction of 54 volt e- angle of 50° between incident and scattered beam can be termed as the diffraction of e- theta = 1/2 (180° - phi)

phi = 50°, theta = 1/2 (180° - 50°)

= 1/2 × (130°) = 65°

according to Bragg's law , for first order diffraction maximum (n=1)

2d sin theta = 1 × lambda

or lambda = 2d sin theta

for nickel crystal, the distance between atomic planes, d= 0.91 Armstrong

therefore, lambda = 2 × 0.91 × sin65°

= 1.66 Armstrong

Niw, wave nature of e- and hence the de-broglie hypothesis will be confirmed, if De-broglie wavelength of e-, when accelerated through 54 volt comes out to be 1.66 Armstrong.

Putting V = 54 volt in

lambda = 12.27 × 10^-10m

root (V)

or 12.27 Armstrong

root (V)

lambda = 12.27 Armstrong

root (54)

1.65 Armstrong.

Answer 2

Answer:

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