Can u plzzzz help me to find a circumference
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36-(2×17)=2=Diameter
Radius(r) =2/2=1
:. Circumference of the semicircle above the rectangle =2 ×pi ×r
=2×3.14×1
=6.28 cm.
Since the given quadrilateral is rectangle, breadth=14cm.=Diameter of the inner semicircle.
Radius(r')=14/2=7cm.
:. Circumference of the inner semicircle =2×pi×r'
=2×3.14×7 cm.
=43.96 cm.
THANK YOU.........
HOPE THIS IS HELPFUL.............
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