Can u prove that the sum of angle of a triangle is equal to 180⁰
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Step-by-step explanation:
Given :
A triangle ABC.
To prove :
∠A+∠B+∠C=180o⟹∠1+∠2+∠3=180o
Construction :
Through A, draw a line l parallel to BC.
Thus,
Therefore, ∠2+∠3=∠4+∠5
∠1+∠2+∠3=∠1+∠4+∠5 [adding∠1bothSide]
∠1+∠2+∠3=180o
Thus, the sum of three angles of a triangle is 180o
Answered by
1
Step-by-step explanation:
draw a line parallel to BC and it has to go through A
and call that line as LM
so angle LAB = angle ABC( alternative angles)
same way angle MAC= angle ACB
so angle at A is straight angles
that means
angle LAB+angle BAC+angle CAM= 180
so
angle ABC+angle BAC+angle ACB=180
hence proved
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