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Ammonia gas is N H₃ . Molecular mass = 14 + 3 = 17 amu
(ii)
(a)Number of moles of Ammonia in 68 gms = 68/17 = 4 moles
(b)1 mole of an ideal gas occupies 22.4 liters at STP
Hence 4 moles occupy 4 * 22.4 = 89.6 liters
(iii)Number of molecules present in four moles of an ideal gas at any temperature and pressure = 4 * Avogadro number = 4 * 6.023 * 10^23
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(ii)
(a)Number of moles of Ammonia in 68 gms = 68/17 = 4 moles
(b)1 mole of an ideal gas occupies 22.4 liters at STP
Hence 4 moles occupy 4 * 22.4 = 89.6 liters
(iii)Number of molecules present in four moles of an ideal gas at any temperature and pressure = 4 * Avogadro number = 4 * 6.023 * 10^23
CLICK THANK YOU
sword21:
Thank you very much
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