Question

can u sol eg 3......​

Answer 1

Answer:

yes i can

BUT IT IS LONG IT CAN TAKE TIME

Step-by-step explanation:

AREA OF SEGMENT AYB=SECTOR'S AR OYAB-TRIANGLE AREA OAB

• AREA OF SECTOR =120/360×22/7×21×21=462CM^2

NOW M IS MID POINT OF AB AND ANGLE AOM=BOM=1/2×120=60 DEGREE

om =x cm

om/oa=cos 60

x/21=1/2

x=21/2(dont solve to decimal )

om =21/2

am/ao=sin60=root3/2

am=21root3/2

so,ab=2am =2×21root3/2=21root3cm

ar of triangle aob=1/2×ab×om=1/2×21root3×21/2cm^2

=441/4×root3 cm2

so area of segment BYA=(462-441/4×root 3)cm^2

hope it help you

that was a though que

have a good day

Answer 2

Answer:

area of the segment AYB = 271.04cm²

Step-by-step explanation: