Question

can u solve it for me????

Answer 1

no i cannot because i did not understand the question

Answer 2

$3 \: \: points \: \: can \: \: be \: \: taken \: \: at \: \: random \\ from \: \: 8 \: \: points \: \: in \: \frac{8!}{3 !\times (8 - 3)!} \\ = 56 \: \: ways \\ \\ 3 \: \: non - collinear \: \: points \: \: form \\ 1 \: \: triangle \\ \\ each\: \: non - collinear \: \: points \: \: form \: \: \\ 10\: \: triangles \: \: with \: \: collinear \: \: points \\ so \: \: 3 \: \: makes \: \: 30 \: \: triangles \\ \\ therefore \: \: required \: \: probability \\ = \frac{31}{56}$