Question

can u solve the 16th one???

Answer 1

Answer:

A = 30, B = 42, C = 28

Step-by-step explanation:

Given that,

$\frac{A+B}{2}$ = 36

$\frac{B +C}{2}$ = 35

$\frac{A+C}{2}$= 29

∴ A + B = 72

B + C = 70

A + C = 58

Now,

B = 70 - C and C = 58 - A

Therefore B = 70 - 58 +A

Substituting the value of B in eq A +B = 72

A + 70 - 58 + A = 72

2A + 12 = 72

2A = 60

A = 30

∴ B = 12 +A = 42

C = 58 - A = 28

Answer 2

✯ Solution

We need find the Age of A and we are provided with the following data :

• The average age of A and B is 36 years
• The average age of B and C is 35 years
• The average age of A and C is 29 years

Average age of A and B is 36 years

$:\implies\sf{(A+B)/2=36}\implies\sf{A+B=72\quad\dashrightarrow1}$

Average age of B and C is 35 years

$:\implies\sf{(B+C)/2=35}\implies\sf{B+C=70\quad\dashrightarrow2}$

Average age of A and C is 29 years

$:\implies\sf{(A+C)/2=29}\implies\sf{A+C=58\quad\dasharrow3}$

$\to\sf{A+B+B+C=70+72}$  --- [Adding Equation 1 and Equation 2]

$\to\sf{A+C+2B=142}$             --- [We combined like terms here]

$\to\sf{58+2B=142}$                   --- [From Equation - 3]

$\to\sf{2B=142-58=84}$          --- [Subtracting 58 from Both Sides]

$\to\sf{B=42}$                              --- [Dividing both Sides by 2]

Substitute the value of B in Equation 1

$\to\sf{A+42=72}$                      --- [Since B = 42]

$\to\sf{A=72-42}$                      --- [Subtracting 42 from both sides]

$\boxed{\boxed{\to\sf{A=30}}}$