can u solve the circled one
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√2x² + 7x + 5√2 = 0
√2x² + 2x + 5x + 5√2 = 0
√2x(x + √2) + 5(x + √2) = 0
(x + √2)(√2x + 5) = 0
therefore,
x = - √2. OR. x = -5/√2
√2x² + 2x + 5x + 5√2 = 0
√2x(x + √2) + 5(x + √2) = 0
(x + √2)(√2x + 5) = 0
therefore,
x = - √2. OR. x = -5/√2
Strangercitizen1525:
Thanks for the and
ans
but the question is solve by completing the square method and urs is factorization
ok
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