Question

Can u solve this...?​

Answer 1

☞

The equation through loop I1 is

−2+3I1+1+2(I1−I2 )=0

The equation through loop I2 is

−3+4I2 +1+2(I2 −I1 )=0

On solving we get

I1 = 5/13 A

I1 = 5/13 AI2 = 6/13 A

Current through 2Ω will be I1-I2 = 1/13A

I)Potential difference between points B and D will be

V=IR

(1/13×2)

(1/13×2)(2/13)

ii)The potential difference between G and H will also be same as that of between B and D.

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