Question

can u solve this if a+2b+c=0
show that
(a)³+(2b)³(c)³=6abc
i will mark as brainliest

Answer 1

Answer:Proved.Plz mark as brainliest.

Step-by-step explanation:

a+2b+c =0

(a+2b+c)^3=a^3+b^3+c^3+6a^2b+6ab^2

0=a^3+b^3+c^3+6ab(a+b)

a^3+b^3+c^3=-6ab(-c)

a^3+b^3+c^3=6abc.

Answer 2

Given

a + 2b + c = 0

a + 2b = - c

on cubing both sides

( a + 2b )^3 = ( - c )^3

a^3 + 8b^3 + 3a×2b (a +2b ) = - c^3

a^3 + 8b^3 + 6ab (a + 2b ) = - c^3

we know a + 2b = - c

a^3 + 8b^3 + 6ab (- c) = - c^3

a^3 + 8b^3 +c^3 -6abc = 0

a^3 + 8b^3 + c^3 = 6abc

Hope it helps

Pls mark it brainliest.