Math, asked by geniusforever, 1 year ago

can u solve this problem ????~

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Answered by Anonymous
1

Sec^2θ + Cosec^2θ can never be less than 2.

If possible let it be less than 2.

1 + Tan^2θ + 1 + Cot^2θ < 2.

⇒   2 + Tan^2θ + Cot^2θ

⇒   (Tanθ + Cotθ)^2 < 2.

Which is not possible.


Anonymous: aapko kya samaj ni aaya usme
geniusforever: hi
Anonymous: hloo
geniusforever: can u explain from first... step by step please!
Anonymous: okk
geniusforever: thanks dear
Anonymous: u asked to prove......never less than 2......I have prove this Q. from contradiction...…...mene let kr liya ki ye less than 2 h...…..but in last 2 + tan^2 theta +cot^2 theta aaya …...jo ki obvious h 2 se bda h...….therefore jo hmne let kiya tha vo wrong h.....AND HENCE THIS Eqn IS NEVER LESS THAN 2
geniusforever: very very very thanks dear...i understood it
geniusforever: can u follow me please
Anonymous: okkk
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