Math, asked by KunalShenoy, 1 year ago

Can u solve this :- Prove that sec3A + cosec3A = secA X cosecA

Answers

Answered by newton82

sec3A+cosec3A=secA/cosecA
The question is wrong secA x cosecA should be secA/cosecA.
Now,
$\frac{cotA}{cosecA} +\frac{cosA}{cotA}=\frac{secA}{cosecA} \\ \frac{cotA(cotA+1)}{cotA\times cosecA}=\frac{secA}{cosecA}\\We \:know\: cotA+1=secA\\So,\\ \frac{secA}{cosecA}=\frac{secA}{cosecA}$

KunalShenoy: hey bro it is a cube and not 3 PLEASE ANSWER ONLY IF U KNOW IT

newton82: oh its cube not 3

KunalShenoy: yes buddy

newton82: sorry buddy this can't be solved ihave just ask a professor of university ,he said the question is wrong

newton82: dont use your head on this the question is wrong

KunalShenoy: ok

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