Question

Can u solve this :- Prove that sec3A + cosec3A = secA X cosecA

Answer 1

sec3A+cosec3A=secA/cosecA
The question is wrong secA x cosecA should be secA/cosecA.
Now,
$\frac{cotA}{cosecA} +\frac{cosA}{cotA}=\frac{secA}{cosecA} \\ \frac{cotA(cotA+1)}{cotA\times cosecA}=\frac{secA}{cosecA}\\We \:know\: cotA+1=secA\\So,\\ \frac{secA}{cosecA}=\frac{secA}{cosecA}$