can u solve this question
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The answer is.. 4x and 5y
Step-by-step explanation:
As per the question 16x^2 — 25y^5
We know that 4^2 = 16 and 5^2 = 25
(a+b) (a—b) = a^2 — b^2
a= 4x ; b= 5y
(4+5)(4—5)=(4x)^2 — (5y)^2
= 16x ^2— 25y^2
Therefore x= 4 and y= 5
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