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anirudha20:
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Given
Sum(P) =₹5000
Time(t)=2yr
Successive rate =6% and 8%
So rate of interest for 1yr =6%
Amount = p(1+r/100)^n
Here n=1, p=5000, r=6%
Amount = 5000(1+6/100)^1
=5000x(106/100)
=50x106
=5300
After 1st year rate changes to 8% then sum=₹5300
R=8%
N=1
Amount = p(1+r/100)^n
=5300(1+8/100)
=5300x108/100
=53x108
=5724
AMOUNT HE GET AFTER 2 YRS =5724
Compound interest = amount - sum
=5724-5000
=₹724
This is your ans hope it will help you in case of any doubt comment below
Sum(P) =₹5000
Time(t)=2yr
Successive rate =6% and 8%
So rate of interest for 1yr =6%
Amount = p(1+r/100)^n
Here n=1, p=5000, r=6%
Amount = 5000(1+6/100)^1
=5000x(106/100)
=50x106
=5300
After 1st year rate changes to 8% then sum=₹5300
R=8%
N=1
Amount = p(1+r/100)^n
=5300(1+8/100)
=5300x108/100
=53x108
=5724
AMOUNT HE GET AFTER 2 YRS =5724
Compound interest = amount - sum
=5724-5000
=₹724
This is your ans hope it will help you in case of any doubt comment below
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