can u tell this answer please
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i hv snd u reference.
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vaishnavi51:
it is not clear
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let A and D be 1x and 2x respectively.
A+D=180°. [AB¶CD] {interior angles on same side of transversal}
x+2x=180°
3x=180°
x=60°
Therefore A=60°, D=120°
also,
let C and B be 4y and 5y respectively.
C+B=180°. [AB¶CD] {interior angles on same side of transversal}
4y+5y=180°
9x=180°
y=20°
Therefore C=80°, B=120°
Trapezium can be the quadrilateral ABCD, where two sides are parallel.
A+D=180°. [AB¶CD] {interior angles on same side of transversal}
x+2x=180°
3x=180°
x=60°
Therefore A=60°, D=120°
also,
let C and B be 4y and 5y respectively.
C+B=180°. [AB¶CD] {interior angles on same side of transversal}
4y+5y=180°
9x=180°
y=20°
Therefore C=80°, B=120°
Trapezium can be the quadrilateral ABCD, where two sides are parallel.
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