can we construct a triangle of a triangle ABC with ab is equal to 4 cm angle is equal to 120 cm and angle b is equal to 75 centimetre
Answers
Answer: Hello dear,
The steps for the construction above are as follows:-
1. Draw BC = 5 cm and construct angle B = 120° ( either with protractor or compass, I have done using a compass).
2. Cut the ray of angle B at A with an arc of 4 cm. Join AC.
3. Draw ray BX such that angle CBX is an acute angle.
4. Cut the ray BX in 5 parts of equal length.
5. Name them as B1, B2, B3, B4 and B5. Join CB5.
6. Through B4, draw a line parallel to CB5 which intersects BC at C'.
7. Through C', draw another line parallel to AC which intersects AB at A'.
8. ∆A'BC' is the required triangle.
Hope you got the correct answer.
Please mark me as the brainliest.
Answer:
Steps:
1. draw base AB=4cm
2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc.
3. let C be the point of intersection of the above 2 lines.
4. draw a ray AX making an acute angle with line AB on the opposite side if the vertex C.
5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1
6. join A3B and draw a parallel line B
′
A2
7. draw a line parallel to BC to intersect AC at C
′
Thus AB
′
C
′
is a required triangle.
Justification;
By construction,
AB
AB
′
=
AA3
AA2
=
3
2
also B
′
C
′
∥BC
∴∠AB
′
C
′
=∠ABC
In △AB
′
C
′
,△ABC
∠A=∠A
∠AB
′
C
′
=∠ABC
△AB
′
C
′
∼△ABC
⇒
AB
AB
′
=
AC
AC
′
=
BC
B
′
C
′
∴
AB
AB
′
=
AC
AC
′
=
BC
B
′
C
′
=
3
2