Question

can we draw a triangle of vertices (1,5)(5,8)and(13,14​

Answer 1

Step-by-step explanation:

we can't draw a triangle of given vertices because here, area of triangle is zero..

Let A(1, 5), B(5, 8) and C(13, 14)

⇒ AB = √(5-1)^2 + (8-5)^2

AB = √4^2 + 3^2 √ 25

AB = 5

⇒ BC = √ (13-5)^2 + (14-8)^2

BC = √ 8^2 + 6^2 = √ 100

BC = 10

⇒ AC = √(13-1)^2 + (14 - 5) ^2

AC = √ 12^2 + 9^2 = √225

AC = 15

Largest side is AC = 15 which is equal to Sum of other two sides AB and BC i.e.

(10 + 5 = 15)

∴ triangle cannot be drawn infact the points are collinear

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