Question

can we find the hcf of 1.2 and 0.12? justify your answer

Answer 1

For this we need to use class 10 concept which is Euclid's Division Lemma which says that

a = bq + r where a dividend , b is divisor , q is quotient and r is remainder and
0 <= r < b

a>b

So take a = 1.2 and b=0.12

1.2=0.12×10+0

We will have the last divisor as the HCF which is 0.12

Therefore HCF of 1.2 and 0.12 is 0.12

Answer 2

Answer:

Step-by-step explanation:

Let’s take two fractions (a/b) and (c/d).

To find LCM and HCF of (a/b) and (c/d) the generalized formula will be:

H.C.F = H.C.F of numerators / L.C.M of denominators

L.C.M = L.C.M of numerators / H.C.F of denominators

so,HCF of (1.2 , 0.12) =HCF of (12/10 , 12/100)=HCF of (12, 12) /LCM of (10, 100)

since=>HCF of (12 , 12) = 12 and LCM of (10 , 100) = 100

so, HCF of (1.2 , 0.12) =12/100 =0.12