can we form triangle with sides 6cm, 7cm, 8cm
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Step-by-step explanation:
Let AB =6, AC = 7 and BC = 8 cm
Since BC is the largest side, A is the largest angle.
Let angular bisector of A meet BC at D.
We need to find lengths of BD, DC and hence the shortest segment.
As per the angular bisector theorem
BD / DC = AB / AC
So BD / DC = 6 / 7
Now BD + DC = BC = 8
Solving we get,
BD = 48/13 cm, DC = 56/13 cm or
3.69 cm and 4.31 cm respectively
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