can we solve the 'first part' of this question by this method....
In ∆AOB and ∆AOC
AB=AC (Given)
AngleB÷2 =AngleC÷2 (Bisects of angleB and angleC)
AO=AO ( Common)
thus,∆AOB is congruent to ∆AOC by SAS
So, OB=OC (CPCT)
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Step-by-step explanation:
Your method is correct.
You just need to add a point that ∠B = ∠C ( Angles opposite to equal sides AB and AC)
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