Can (x-1) be a remainder while dividing x-3x 5x-6 by (x square +3)?
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Answered by
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Answer:
on dividing x^4-3x^2+5x-9 by x^2+3. we get the. quotient = x^2-6. and remainder = 5x+9. hence , it is not possible to get ...
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Answered by
0
Answer:
No
Step-by-step explanation:
Multiply the Divisor with the Quotient
So (x-1)(x^2+3)
We get (x^3)-(x^2)+(3x)-3
It is not our dividend
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