can (x-5) bcane the remainder on division of a polynomial p(x) by (5x+20)?
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The Remainder Theorem starts with an unnamed polynomial p(x), where "p(x)" just ... completed division: quotient x^2 + 4x + 9, remainder 30 ... That is, when you divide by "x – a", your remainder will just be some number. ... For x = –4 to be a solution of f (x) = x6 + 5x5 + 5x4 + 5x3 + 2x2 – 10x – 8 = 0, it must be that f (–4) = 0.
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