can you answer it the 2nd question
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Area of the trapezium ABCD = AB/2 (AD + BC)
24.5 = (AB/2) (10 + 4)
49 = AB (14)
AB = 3.5 cm
Radius of the quadrant of the circle = AB = 3.5 cm
Area of the quadrant of the circle = 1/4πr²
= 1/4 x 22/7 x 3.5 x 3.5
= 9.625 cm2
Area of the shaded region = Area of the trapezium - Area of the quadrant of the circle
= 24.5 - 9.625
= 14.875 cm2
Hope it'll Help
24.5 = (AB/2) (10 + 4)
49 = AB (14)
AB = 3.5 cm
Radius of the quadrant of the circle = AB = 3.5 cm
Area of the quadrant of the circle = 1/4πr²
= 1/4 x 22/7 x 3.5 x 3.5
= 9.625 cm2
Area of the shaded region = Area of the trapezium - Area of the quadrant of the circle
= 24.5 - 9.625
= 14.875 cm2
Hope it'll Help
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