can you answer these questions
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Heya.....!!!
When the force and displacement are in opposite direction then the work done is negative .
So ,, if work done =>> F×D×Cos(theta )
when theta = 180°
W = - F×D [[ cos180° => -1 ]]
hence , negative work done when theta = 180°.
HOPE IT HELPS U ☺
pls mark it as brainliest
When the force and displacement are in opposite direction then the work done is negative .
So ,, if work done =>> F×D×Cos(theta )
when theta = 180°
W = - F×D [[ cos180° => -1 ]]
hence , negative work done when theta = 180°.
HOPE IT HELPS U ☺
pls mark it as brainliest
rohit710:
thanks for choosing as brainliest
plz made me also
lol .... blocked....so what? haha, stupid go to hell
Answered by
5
Work is the dot product of force and displacement
Work =F.x
=Fxcos(theta)
Obviously F and x are positive since we take their magnitude
so now for work to be negative only option is that cos(theta) should be negative
cos(theta) is negative from 91 degree to 180degree
So from above option we can say that 180 degree is the answer
Mark as brainliest :)
Work =F.x
=Fxcos(theta)
Obviously F and x are positive since we take their magnitude
so now for work to be negative only option is that cos(theta) should be negative
cos(theta) is negative from 91 degree to 180degree
So from above option we can say that 180 degree is the answer
Mark as brainliest :)
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