Question

Can you answer this?

Answer 1

f1 = 6i + 2j + 3k    |f1| = 7 unit vector along f1 =  6i/7 + 2j/7 + 3k/7
f2 = 3i - 2j + 6k     |f2| = 7 unit vector along f2 = 3i/7  - 2j/7 + 6k/7
f3 = 2i - 3j + 6k     |f3| = 7  unit vector along f3 = 2i/7 - 3j/7 + 6k/7

now F₁ = 5f1 ,  F₂ = 3f2  ,  F₃ = 1f3

so we've forces  
                     
         F₁ = 30i/7 + 10j/7 + 15k/7
        F₂ = 9i/7 - 6j/7 + 18k/7
        F₃ = 2i/7 - 3j/7 + 6k/7

now adding all vectors F(net) = 41i/7 + j/7 + 39k/7  |F| =56.59 N

hope my ans right...........if so mark as brainliest.....if doubts , do ask