Question

can you answer this
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Answer 1

Answer:

${x }^{2} - 4x + 4 - {x}^{2} - 4x - 4 \\ - 8x = 0 \\ x = any \: number$

Answer 2

Answer:

2,-2

Step-by-step explanation:

Zeros = (x - 2)² = 0 ⇒  x = 2

(x + 2)² = 0 ⇒ x = -2

Zeros are 2,-2

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