can you answer this
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tanishq972003:
hey mate mark as BRAINLIEST
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In triangles BCE and BCD,
EC is perpendicular to AB and BD is a perpendicular to AC
Angle E and angle D are congruent............... (each 90°)
BD = EC............................. (given)
BC = BC........................... (common side)
Therefore,
Triangle BCE = triangle BCD ...................(By hypotenuse side test)
Hope this helps! Please mark my answer as brainliest! Have a great day ahead!
EC is perpendicular to AB and BD is a perpendicular to AC
Angle E and angle D are congruent............... (each 90°)
BD = EC............................. (given)
BC = BC........................... (common side)
Therefore,
Triangle BCE = triangle BCD ...................(By hypotenuse side test)
Hope this helps! Please mark my answer as brainliest! Have a great day ahead!
hii
who did
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HEY MATE,
GIVEN : IN ΔABC, BD=CE, BD PERPENDICULAR ON AC AND CE PERPENDICULAR ON AB.
TO PROVE : Δ BDC =~ ΔCBE.
PROOF = IN Δ BDC AND Δ CBE
CB = CB - (COMMON)
BD = CE - (GIVEN)
ANGLE BDC = ANGLE CEB - (EACH - 90)
THEREFORE, Δ BDC =~ Δ CBE - (SAS)
I HOPE THIS WILL HELP YOU...
PLS MARK AS BRAINLIEST.
GIVEN : IN ΔABC, BD=CE, BD PERPENDICULAR ON AC AND CE PERPENDICULAR ON AB.
TO PROVE : Δ BDC =~ ΔCBE.
PROOF = IN Δ BDC AND Δ CBE
CB = CB - (COMMON)
BD = CE - (GIVEN)
ANGLE BDC = ANGLE CEB - (EACH - 90)
THEREFORE, Δ BDC =~ Δ CBE - (SAS)
I HOPE THIS WILL HELP YOU...
PLS MARK AS BRAINLIEST.
i copied thia from the net and you can see there's included angle mentioned
okay
oh see now you copy so mate mark me as BRAINLIEST as she copied
did you report my answer?!
nope
copy what
I told both are right
i didn't copy anything
she is not an expert or a moderator to verify that you are right
pls mark as BRAINLIEST
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