Question

Can you answer this fast

Answer 1

Answer:

95°

/AOC + /BOD = 85°

And AOC +BOD +COD = 180°

/COD = 95°

Answer 2

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$\huge\underline\mathrm{GiVeN}$

• AOB is a straight line. So, ∠AOB = 180°
• ∠AOC + ∠BOD = 85°

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$\huge\underline\mathrm{To FiNd:-}$

• ∠COD = ?

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➨∠AOC + ∠BOD + ∠COD = ∠AOB

➨ 85° + ∠COD = 180°

➨∠COD = 180° - 85°

➨∠COD = 95°

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$<marquee>$hope it helps you.......