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(i)angle EPA =angle DPB
adding angle EPD both sides
therefore angle DPA=angleEPB
In triangle DAP and triangleEBP
angle BAD=angle ABE(GIVEN)
AP=BP(P IS MID POINT OF AB)
angleDPA=angleEPB (PROVED ABOVE)
Therefore,tri. DAP is congruent to tri. EBP
(ii) AD=BE (CONGRUENT PART OF CONGRUENT TRIANGLE)
adding angle EPD both sides
therefore angle DPA=angleEPB
In triangle DAP and triangleEBP
angle BAD=angle ABE(GIVEN)
AP=BP(P IS MID POINT OF AB)
angleDPA=angleEPB (PROVED ABOVE)
Therefore,tri. DAP is congruent to tri. EBP
(ii) AD=BE (CONGRUENT PART OF CONGRUENT TRIANGLE)
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