Math, asked by tania1234, 1 year ago

can you answer this question ???​

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Answered by Anonymous
14

\mathrm{\bigstar\;\;Mean = \dfrac{Sum\;of\;all\;Observations}{Total\;Number\;of\;Observations}}

●  Mean of 15 Numbers is 35

\mathrm{\implies \dfrac{Sum\;of\;15\;Numbers}{15} = 35}

\mathrm{\implies Sum\;of\;15\;Numbers = (35 \times 15)}

\mathrm{\implies Sum\;of\;15\;Numbers = 525}

\mathrm{\implies Sum\;of\;10\;Numbers + Sum\;of\;5\;Numbers = 525}

●  Five numbers are excluded, Mean of 10 remaining numbers = 28

\mathrm{\implies \dfrac{Sum\;of\;10\;remaining\;Numbers}{10} = 28}

\mathrm{\implies Sum\;of\;10\;remaining\;Numbers = 280}

\implies \text{280 + Sum of 5 Excluded Numbers = 525}

\implies \text{Sum of 5 Excluded Numbers = 525 - 280}

\implies \text{Sum of 5 Excluded Numbers = 245}

\implies \mathrm{\dfrac{Sum\;of\;5\;Excluded\;Numbers}{5} = \dfrac{245}{5}}

\implies \text{Mean of Excluded 5 Numbers = 49}


tania1234: thank you so much
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