Question

can you answer this question....if you can plz have proper and full answer.....
I will mark u r answer as Brainlist​

Answer 1

Answer:

Step-by-step explanation:

Since πi < θ < 3πi/2, we are in the third quadrant. Both sin and cos functions are negative in this quadrant.

Sinθ = -4/5.

Cosθ = √ 1 - sin²θ = √ 1 - (-4/5)² = √ 1 - 16/25 = √9/25 = ±3/5

But since θ is in third quadrant cosθ can only be negative i.e. cosθ = -3/5

a) Sin2θ = 2SinθCosθ = 2 * (-4/5) (-3/5) = 24/25.

b) cos2θ = cos²θ - sin²θ = (-3/5)² - (-4/5)² = 9/25 - 16/25 = - 7/25.

c)Tan2θ = sin2θ/cos2θ  = 24/25 / -7/25 = - 24/7.