Question

can you calculate it please

Answer 1

R=4+20=24ohm

I=V/R=6/24=1/4

Answer 2

Mera bhi yahi set tha****

See:

(a) V= 6V

   Total resistance, R= 4+ 20(both are in series)

(b)V= IR

I= 6/24

I= 0.25 A

(c) (i) Let potential difference along electric lamp be V1.

V1= I×R1 (let resistance of lamp be R1) (current through the circuit will be              same as it is in series connection)

V1= 0.25×20

V1= 5V

(ii) Let V2 be potential and R2 be resistance of conductor.

V2= 0.25× 4

V2= 1V

(d) Power of lamp= V1×I

     P= 5×0.25

     P= 1.25V