Question

*Can you crack the logic?*
Question of IIM-B
This is a very interesting and intelligent question..
If 1 1 1 1= 82 %
2 2 2 2= 80 %
3 3 3 3= 95 %
4 4 4 4= 86 %
Then
*5 5 5 5= ?*
Challenge to all master brains! *Explain the answer with logic.*

Answer 1

5 5 5 5 = 75%

Step-by-step explanation:

1 + 1 + 1 + 1 = 4 (in words) FOUR = last letter of the word is R.

Now find it's alphabetical number R = 18 ( 100 - 18) = 82%

2 + 2 + 2 + 2 = 8 (in words) EIGHT = last letter of the word is T.

Alphabetical number of T = 20 (100 - 20) = 80%

3 + 3 + 3 + 3 = 12 (in words) TWELVE = last letter of the word is E.

Alphabetical number of E = 5 (100 - 5) = 95%

4 + 4 + 4 + 4 = 16 (in words) SIXTEEN = last letter of the word is N.

Alphabetical number of N = 14 (100 - 14) = 86%

5 + 5 + 5 + 5 = 20 (in words) TWENTY = last letter of the word is Y.

Alphabetical number of Y = 25 (100 - 25) = 75%

Therefore, 5 5 5 5 = 75%

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