Question

*Can you crack the logic?*

Question of IIM-B

This is a very interesting and intelligent question..


If 1 1 1 1= R

2 2 2 2= T

3 3 3 3= E

4 4 4 4= N

Then

*5 5 5 5= ?*

Challenge to all master brains!

*Explain the answer with logic.*​

Answer 1

Answer:

1+1+1+1=Four R is the last letter

2+2+2+2=Eight T is the last letter

3+3+3+3=Twelve E is the last letter

4+4+4+4=Sixteen N is the last letter

5+5+5+5=Twenty Y is the last letter

So 5 5 5 5=Y

plz mark it as the brainliest answer

Answer 2

Answer:

5 5 5 5= Y

Step-by-step explanation:

In the first case,

1+1+1+1= Four, which ends with R

In the second case,

2+2+2+2= Eight, which ends with T

In the third case,

3+3+3+3= Twelve, which ends with E

In the forth case,

4+4+4+4= Sixteen, which ends with N

In the fifth case,

5+5+5+5= Twenty, which ends with Y

Therefore, 5 5 5 5= Y