Question

*Can you crack the logic?

This is a very interesting and intelligent question..


If 1 1 1 1= R

2 2 2 2= T

3 3 3 3= E

4 4 4 4= N

Then

*5 5 5 5= ?*

Without help of Google please
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Answer 1

Answer:

please mark the answer as brainliest

Step-by-step explanation:

1+1+1+1= FOUR (R)

2+2+2+2=EIGHT (T)

3+3+3+3=TWELVE ( E)

4+4+4+4=SIXTEEN (N)

5+5+5+5=TWENTY (Y)

Thinking in different way can crack any logic .

It's a pattern of the number name of the sum of each of these digits ending with these letters.

Answer 2

Given:

1 1 1 1= R

2 2 2 2= T

3 3 3 3= E

4 4 4 4= N

To find:

5 5 5 5= ?

Solution:

⇒1 1 1 1 = 1 +1 +1+ 1= 4(FOUR) = last letter =R

⇒2 2 2 2= 2+2+2+2= 8(EIGHT) = last letter =T

⇒3 3 3 3 = 3+3+3+3 = 12= 1+2=3(THREE) = last letter =E

⇒4 4 4 4 = 4+4+4+4= 16=1+6=7(SEVEN) = last latter =N

Similarly:

⇒5 5 5 5= 5+5+5+5= 20= 2+0 =2 (TWO)= last letter = O

The final answer is = "O"