Question

*Can you crack the logic?*

This is a very interesting and intelligent question..

If 1 1 1 1= R

2 2 2 2= T

3 3 3 3= E

4 4 4 4= N

5 5 5 5= O ( its an O and not zero)

6 6 6 6=?

Challenge to all master brains!

*Explain the answer with logic.*

Answer 1

Answer: X

Explanation:

1111 =4;  fou(r)

2222=8; eigh(t)

3333= 12; 1+2= 3 ; thre(e)

4444= 16; 1+6=7 ; seve(n)

5555= 20; 2+0= 2 ; tw(o)

6666=24; 2+4= 6; si(x)

So answer is X.

Answer 2

Given :

1 1 1 1= R

2 2 2 2= T

3 3 3 3= E

4 4 4 4= N

5 5 5 5 = I

To Find :

6 6 6 6 =?

Solution :

First, find out the logic behind the given code.

1 1 1 1= R

=> 1 + 1 + 1 + 1 = 4

=> Four => last letter is R

2 2 2 2 = T

=> 2+2+2+2 = 8

=> Eight => last letter is T

3 3 3 3 = E

=> 3+3+3+3 = 12 = 1+2 3

=> Three => Last letter is E

4 4 4 4 = N

=> 4+4+4+4 = 16 = 1+6 = 7

=> Seven => last letter is N

5 5 5 5 = 0

=> 5+5+5+5 = 20 = 2+0 = 2

=> Two => Last letter is O

In the same way, find out 6 6 6 6 =?

6 6 6 6 =?

=> 6+6+6+6 = 24 = 2+4 = 6

=> Six = > Last letter is x

Hence, 6 6 6 6 = X