Can you do this???????
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d(log cos√x )/dx = 1/cos√x × (-sin√x) × 1/2√x
= -tan√x/2√x
= -tan√x/2√x
vidushi99:
secxtanx + log tan(π/4+x/2)
can u do this?
secxtanx me uv rule so secx(sec^2(x))+tanx(secxtanx)
uske baad for part 2 me composite function
so 1/(tan(π/4+x/2)*1/2
*sec^2(π/4+x/2
done
overall answer 0.5sec^2(π/4+x/2)/(tan(π/4+x/2)) +sec^3(x) +secxtan^2(x)
Thanks a lot mate
:) np
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