Can you do this fast by using formula?Please fast. All three..
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Hi ,
x - y = 7 ----( 1 )
x³ - y³ = 133 -----( 2 )
We know the algebraic identity
( x - y )³ = x³ - y³ - 3xy( x - y )
7³ = 133 - 3xy × 7
343 = 133 - 21xy
21xy = 133 - 343
21xy = -210
xy = -210 / 21
xy = -10
I hope this helps you.
:)
x - y = 7 ----( 1 )
x³ - y³ = 133 -----( 2 )
We know the algebraic identity
( x - y )³ = x³ - y³ - 3xy( x - y )
7³ = 133 - 3xy × 7
343 = 133 - 21xy
21xy = 133 - 343
21xy = -210
xy = -210 / 21
xy = -10
I hope this helps you.
:)
Answered by
2
(x - y)³ = x³ - y³ - 3xy(x - y)
7³ = 133 - 3xy × 7
343 = 133 - 21xy
21xy = 133 - 343
21xy = -210
xy = -210 / 21
xy = -10
Therefore, (i)xy = -10
(x+y)² = (x-y)²+4xy
(x+y)² = 7² + 4(-10)
(x+y)² = 49 - 40
x+y = √9
x+y = ±3
(x+y)² = x²+y²+2xy
3² = x²+y² + 2(-10)
x²+y² = 9+20
x²+y² = 29
If we take x = -3 also, x²+y² = 29
7³ = 133 - 3xy × 7
343 = 133 - 21xy
21xy = 133 - 343
21xy = -210
xy = -210 / 21
xy = -10
Therefore, (i)xy = -10
(x+y)² = (x-y)²+4xy
(x+y)² = 7² + 4(-10)
(x+y)² = 49 - 40
x+y = √9
x+y = ±3
(x+y)² = x²+y²+2xy
3² = x²+y² + 2(-10)
x²+y² = 9+20
x²+y² = 29
If we take x = -3 also, x²+y² = 29
mysticd:
x + y = ± 3
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