can you do this sum solution
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(1/3)^5÷(1/3)×(1/3)^-4
according to DMAS we first divide
(1/3)^5÷(1/3)=(1/3)^5-1
(1/3)^4
now,(1/3)^4×(1/3)^-4=(1/3)^4+(-4)
=(1/3)^0
anything to power 0 is 1
So the answer is one
Hope it helps you
according to DMAS we first divide
(1/3)^5÷(1/3)=(1/3)^5-1
(1/3)^4
now,(1/3)^4×(1/3)^-4=(1/3)^4+(-4)
=(1/3)^0
anything to power 0 is 1
So the answer is one
Hope it helps you
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