Question

Can you draw a triangle with vertices 1,5 5,8 and 13,14 give reasons

Answer 1

Answer:

Area of triangle = \frac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})

2

1

[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)

= \frac{1}{2}[1(8-14)+5(14-5)+13(5-8)]

2

1

[1(8−14)+5(14−5)+13(5−8)]

= \frac{1}{2}[1(-6)+5(9)+13(-3)]

2

1

[1(−6)+5(9)+13(−3)]

= \frac{1}{2}[-6+45-39]

2

1

[−6+45−39]

= \frac{1}{2}[0]

2

1

[0]

= 0