Can you explain me the third part of this above question ?
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Side of Bigger square ABCD= β2025 m
= 45 m
Side of smaller Square= 38m (Solved Above)
Let width of Path be x metres
Since path is two times included in one side,
In side AB,
38+x+x= 45 (Since side of small square + two times width of path= Side of large Square)
38+2x=45
x=45-38/2
x=3.5 m. Ans.
= 45 m
Side of smaller Square= 38m (Solved Above)
Let width of Path be x metres
Since path is two times included in one side,
In side AB,
38+x+x= 45 (Since side of small square + two times width of path= Side of large Square)
38+2x=45
x=45-38/2
x=3.5 m. Ans.
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