Can you explain the answer of this question below:
If 7sin2x + 3cos2x = 4 then , secx + cosecx =
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7sin2x + 3cos2x = 4
So, 4sin2x + 3sin2x + 3cos2x = 4
4sin2x + 3 (sin2x + cos2x) = 4
4sin2x + 3(1) = 4
4sin2x = 4 – 3
4sin2x = 1
sin2x = ¼
sin x = ½
So, x = 30 degree.
Now , secx + cosecx = sec30 + cosec30
= (2/root3)+2
= (2+2root3)/root3
= (2root3 + 6)/3.
Hope it help u.....
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