can you factor 6x² + x - 12 using quadratic trinomial (a > 1)
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The standard form of a trinomial is ax2+bx+c
To factor consider factors of product ac that sum to b , the coefficient of the x term.
For 6x2−x−2
a = 6 , b = -1 and c = -2
consider factors of ac =(6×−2)=−12
factors of -12 are ± (1,2,3,4,6,12 ). - 4 and 3 are the required factors
as - 4 + 3 = - 1 = b.
Now replace - x by 3x - 4x
hence: 6x2+3x−4x−2=3x(2x+1)−2(2x+1)
there is now a common factor of (2x + 1 )
⇒6x2−x−2=(2x+1)(3x−2)
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