Question

can you find the largest possible number containing any 9 of 10 digits considering 0 also a number that is divisible by 11 without a remainder​

Answer 1

Answer:

11 is answer because when we divide 11 with 11 then the answer is one

Answer 2

Answer:

The largest possible number containing 10-digits that is divisible by 11 without a remainder is 9,999,999,999.

Step-by-step explanation:

Assumption,

Let the largest possible number be 'x'.

Given,

The number 'x' has 9 - 10 digits.

The number 'x' when divided by 11, then the remainder is zero.

To find,

First, we try to find the largest 10-digit number.

i.e. 9,999,999,999

Now we will see whether this 10-digit is divisible by 11 or not.

9,999,999,999/11 = 909,090,909

As we can clearly see that the 10-digit number 9,999,999,999 is divisible by 11, so this number is following the required condition,

But as this is the highest 10-digit number, so the largest possible number containing 10-digits that is divisible by 11 without a remainder is 9,999,999,999.

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