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17) /_ ABC = /_BCD
So, AB is parallel to CD
/_CEF + /_DCE = 180°
So, EF is parallel to CD
Hence, AB || CD
Sorry, I could only solve one!
So, AB is parallel to CD
/_CEF + /_DCE = 180°
So, EF is parallel to CD
Hence, AB || CD
Sorry, I could only solve one!
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