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Step-by-step explanation:
The given equations are:
3x/2-5y/3=-2
x/3+y/2 = 13/6
Comparing these equations with
a₁x+b₁y+c₁ = 0
and
a₂x+b₂y+c₂ = 0
, we obtain
a₁ = -3; b₁ = -5/3; c₁ = -2
a₂ = 1/3 ; b₂ = 1/2; c₂ = 13/6
a₁/a₂ = 9/2; b₁/b₂ = -10/3; c₁/c₂ = -12/13
Since, a₁/a₂ ≠ b₁/b₂
Hence, the lines representing the given pair of equations have a unique solution and the pair of lines intersects at exactly one point.
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