Math, asked by sandrabennett6161, 6 hours ago

Can you give me an answer to this question sincerely.
I want the correct answer if not I will be reporting .So dont answer if you don't know it!!​

Attachments:

Answers

Answered by EdwinJose
2

Step-by-step explanation:

The given equations are:

3x/2-5y/3=-2

x/3+y/2 = 13/6

Comparing these equations with

a₁x+b₁y+c₁ = 0

and

a₂x+b₂y+c₂ = 0

, we obtain

a₁ = -3; b₁ = -5/3; c₁ = -2

a₂ = 1/3 ; b₂ = 1/2; c₂ = 13/6

a₁/a₂ = 9/2; b₁/b₂ = -10/3; c₁/c₂ = -12/13

Since, a₁/a₂ ≠ b₁/b₂

Hence, the lines representing the given pair of equations have a unique solution and the pair of lines intersects at exactly one point.

Answered by mentorqiqi
0

Step-by-step explanation:

Mark me a brainlist please

Attachments:
Similar questions