Question

can you give me the answer​

Answer 1

Answer:

12

Step-by-step explanation:

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Answer 2

Given that,two numbers in a pythogoras triplet are 5and13

☯️let's consider the other number as x

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$\sf{ \underline{★ \: Pythogoras \: triplet}:}$

➺s²+s²=h²

now,

$⟼ {\blue{ {s}^{2} + {s}^{2} = {h}^{2}}} \: \: \: \: \: \: \\ ⟼ {5}^{2} + {x}^{2} = {13}^{2} \\ ⟼25 + {x}^{2} = 169 \\ ⟼{x}^{2} = 144 \: \: \: \: \: \: \: \: \: \: \: \: \: \\ ⟼x = \sqrt{144} \: \: \: \: \: \: \: \: \: \\ ⟼x = 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\blue{ \underline{\boxed{ \orange {\mathfrak{ \therefore \: \: x = \: \: 12}}}}}$

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